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1.ʹÓÃsysµÇ½,ÈçºÎ²é¿´ÄĸöÓû§ÏµĶÔÏóÕ¼ÓõĴÅÅ̿ռä×î´ó?
2.Ö´Ðвéѯʱ±¨´í:ORA-01652:ÎÞ·¨Í¨¹ý128(ÔÚ±í¿Õ¼äTEMPÖÐ)À©Õ¹temp¶Î£¬²»ÖªÊÇʲôÔÒò£¿
3.ÊäÈë:Ò»¸ö×Ö·û´®¡°35,36,380¡±
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35
36
380
ÓÃsqlÔõôд£¿
4.ʹÓÃselect * from dba_users; µÃµ½passwordֵȫΪ¿Õ£¬²»ÖªÔÒò?
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3.
select substr(regexp_substr(',' || '35,36,380', ',([^,]+)', 1, level), 2) as "item"
from dual
connect by level <= length(regexp_replace('35,36,380', '[^,]', '')) + 1
SQL code:
4.
SQL> select password from dba_users;
PASSWORD
------------------------------
9CC0ECDD8721C8E3
C89E957D620BC4ED
3FB8EF9DB538647C
84B8CBCA4D477FA3
5AC67B98FA46369E
88A2B2C183431F00
B97545C4DD2ABE54
88D8364765FCE6AF
4AA37D1393FD7BB5
4C6D73C3E8B0F0DA
CE4A36B8E06CA59C
ORA-01652ÕâÖÖÎÊÌâÒ»°ãÓÐÁ½ÖÖÔÒò£ºÒ»ÊÇÁÙʱ±í¿Õ¼ä¿Õ¼ä̫С£¬¶þÊDz»ÄÜ×Ô¶¯À©Õ¹£»
3.
SQL code:
select replace('35,36,37',',',chr(10)) from dual
SQL code:
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emp_no emp_name
------- ------------
0001 TOM
0002 JOHN
0003 MARY
³£Óõ绰
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0001,TOM
0002,JOHN
......
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SQL>SELECT SEQUENCE#,APPLIED from V$ARCHIVED_LOG ORDER BY SEQUENCE#;
SEQUENCE# APP
---------- ---
13 NO
13 YES ......
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