python 爬取网页是出现的错误

代码:
    timeout = 10
    socket.setdefaulttimeout(timeout)
    sock = urllib2.urlopen(url)
    html = sock.read()
一般情况能行，运行没问题，可有常常会突然报错
Traceback (most recent call last):
File "/usr/local/lib/python2.5/threading.py", line 486, in __bootstrap_inner
    self.run()
File "spider_eastmoney.py", line 150, in run
    next_page = parse_ (mysqlDB, http, html, mod_name)
File "spider_eastmoney.py", line 94, in parse_
    page_html= http.get_html(pageurl)
File "/home/Spider/News/genericHttp.py", line 47, in get_html
File "/home/Spider/News/genericHttp.py", line 47, in get_html
    html = sock.read()
File "/usr/local/lib/python2.5/socket.py", line 304, in read
    data = self._sock.recv(rbufsize)
File "/usr/local/lib/python2.5/httplib.py", line 529, in read
    s = self.fp.read(amt)
File "/usr/local/lib/python2.5/socket.py", line 328, in read
    data = self._sock.recv(left)
timeout: timed out
这是什么问题，以前没遇过，我用了多线程，线程数我设为1，会不会是这个原因。

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这不是很明显地写着receive timeout吗

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我说，是什么原因造成的

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网络情况造成的...

很正常....

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这种情况需要你