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<filter object at 0x0000000002A2C9E8>
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def map_func(lis):
return lis + 1
li = [1,2,3,4,5]
map_l = map(map_func, li) #½«liÖÐËùÓеÄÊý¶¼+1
print (map_l)
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What's New In Python 3.0 http://blog.csdn.net/t_huanghai/archive/2008/12/04/3443782.aspx
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map() and filter() return iterators. If you really need a list, a quick fix is e.g. list(map(...)), but a better fix is often to use a list comprehension (especially when the original code uses lambda), or rewriting the code so it doesn¡¯t need a list at all. Particularly tricky is map() invoked for the side effects of the function; the correct transformation is to use a regular for loop (since creating a list would just be wasteful).
What's New In Python 3.0
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correct format. mark it.
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