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id name gongzi
1 ÕÅÈý 1000
2 ÀîËÄ 2000
3 ÕÅÈý 2000
4 ÀîËÄ 3000
5 ÍõÎå 3000
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id name gongzi
1 ÕÅÈý 3000
2 ÀîËÄ 5000
3 ÍõÎå 3000
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select * where id=1 and id=2 and id=3
SQL code:
select name,gongzi=sum(gongzi)
from tb
group by name
SQL code:
select [name],sum(gongzi) as gongzi
from gzb
group by [name]
select name,sum(gongzi) from ±í group by name
Ëٶȶ¼ºÜ¿ìÂï
select id, name,gongzi=sum(gongzi)
from tbname
group by id
select [name],[gongzi]=sum(gongzi) from tb group by [name]
gongziÁÐӦΪintÐÍ
SQL code:
select [id], [name],sum(gongzi) as NewGongzi from yourtablename group by [name]
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