用一条sql语句查询三门课程的成绩都大于80分的学生姓名SQL code: select name, count(chengji) as 总分 from 表名 where 总分>80 group by name
1楼的就可以! SQL code: select name from tablename where sum(chengji)>80 group by name
select [name] from biao group by [name] having (sum(chengji)/count([name])) > 80
试试吧。。。。。。,凭感觉写的 是三科都大于80嘞 是每科成绩都大于80分,不是总成绩 select name from biao where name not in (select name from biao where chengji<80) select name from [tableName] where chengji > 80 group by name having count(*) >= 3 胡说,楼上的都是错的。 SQL code:
select [name] from (select [name], min(chengji) min