经典C程序求解

Problem 1
Read Ken Thompson's article ...

char s[] = {
'\t',
'0',
'\n',
'}',
';",
'\n',
'\n',
'/',
'*',
'\n',
(213 lines deleted)
0
};

/* The string s is a
* representation of the body
* of this program from '0'
* to the end.
*/

main(){
  int i;
  printf("char\ts{ } = {\n");
  for(i=0; s[i]; i++)
      printf("\t%d,\n",s[i]);
  printf("%s",s);
}
Compile and run this program. You will have to figure out what goes in the 213 deleted lines. If you want, you can leave the comment out of the string s and out of the program. Explain the output. By itself, this program does not pose any sort of security threat. Explain in your own words what this program has to do with Thompson's Trojan Horse attack.

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没看懂。
printf("%s",s); 执行这句的时候，s[1]的'0'为什么没打出来呢？

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up

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找到那个'0'了，刚才看错行了。
不过还是没看明白木马是怎么回事

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mark

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找到原文了，这是Ken Thompson获得图灵奖的演讲的一部分。
这段代码是一个例子，它可以产生具有自我复制能力的程序。
不过……还是没看懂

Figure 1 shows a s