帮忙把下面个c函数转成c#的

const int num=100
float neiji(float [num]b, float [num]c)
        {
            int p;
            float nj = 0;
            for (p = 1; p < num; p++) nj += c[p] * b[p];
            return nj;

        }

---

C# code:

const int num=100
public float neiji(float[] b, float[] c)
{
float nj = 0;
for (int p = 1; p < b.Length; p++) nj += c[p] * b[p];
return nj;

}

---

引用

C# codeconstint num=100publicfloat neiji(float[] b,float[] c)
        {float nj=0;for (int p=1; p < b.Length; p++) nj+= c[p]* b[p];return nj;

        }

呃,这样的话b.length是不是等于100哟?

---

const int num=100;
        private float neiji( float []b, float []c)
        {
            int p;
            float nj = 0;
            for (p = 1; p < num; p++)
      &nbs