C# 读取xml - .NET技术 / C#

XML code:
<?xml version="1.0"?>
<AutoUpdater>
<URLAddres URL="http://192.168.30.1/"/>
<UpdateInfo>
<Version Num = "1.0.0.1"/>
</UpdateInfo>
<UpdateFileList>
<UpdateFile FileName = "OutlookAddIn.dll"/>
<UpdateFile FileName = "OutlookAddIn.dll.manifest"/>
<UpdateFile FileName = "SetSecurity.dll"/>
</UpdateFileList>
<RestartApp>
<ReStart Allow = "Yes"/>
<AppName Name = "TIMS.exe"/>
</RestartApp>
</AutoUpdater>


我想直接读取里面的子节点
URL 、 Num 和 FileName。。。

最好代码简单
不要用dataset 

---

C# code:

public XmlNode GetConfigSection(string nodePath)
{
return XmlDoc.SelectSingleNode(nodePath);
}
public void GetConfig()
{
XmlDocument doc = new XmlDocument();
string path = AppDomain.CurrentDomain.SetupInformation.ConfigurationFile;
doc.Load(path);

XmlNode node = GetConfigSection("configuration/CustomConfig");
XmlAttributeCollection attributeCollection =