18.String s = "113@ ere qqq yyui"
请输出所有子串
113
ere
qqq
yyui
19. 编写一个程序，将下面的一段文本中的各个单词的字母顺序翻转，
“To be or not to be"，将变成"oT eb ro ton ot eb."。
18:
String[] subs = s.split("[@\\s]");
for中如果长度不为0循环打印出来
19:
String[] subs = s.split("\\s");
for(String sub:subs){
StringBuilder sb = new StringBuilder (sub);
System.out.println(sb.reverse().toString());
}
能具体点吗？ 看不懂饿
[cod public static void main(String[] args) throws Exception {
String s = "113@ ere qqq yyui";
s=s.replaceAll("[^a-zA-Z 0-9]", "");
for (String str: s.split(" ")) {
System.out.println(str);
}
//末尾标点是不是不要反转？
s = "To be or not to be.";//"oT eb ro ton ot eb."。
StringBuffer sBuffer = new StringBuffer();
for (String str: s.split("\\s")) {
char punctuate=' ';
char[] chars = str.toCharArray();
for (int i = chars.length-1;i>=0;i--) {
if (i==chars.length-1 && !Character.isLetter(chars[i])) {
punctuate = chars[i];
continue;
