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±í1
¹¤ºÅ ÐÕÃû
1 Ëν
2 ¬¿¡Òå
±í2
¹¤ºÅ µÃ·Ö ÆÚÊý
1 50 1
1 60 2
1 64 3
²éѯ½á¹û
ÐÕÃû µÃ·Ö£¨ÈýÆÚµÄavg£©
Ëν 58
SQL code:
select ÐÕÃû,µÃ·Ö=avg(µÃ·Ö) from ±í1 A,±í2 B where A.¹¤ºÅ=B.¹¤ºÅ
group by ÐÕÃû
SQL code:
select ÐÕÃû,avg(µÃ·Ö) as µÃ·Ö
from ±í1 inner join ±í2 on ±í1.¹¤ºÅ=±í2.¹¤ºÅ
group by ÐÕÃû
SQL code:
select a.¹¤ºÅ,a.ÐÕÃû,µÃ·Ö=avg(b.µÃ·Ö)
from ±íÒ» a inner join ±í¶þ b on a.¹¤ºÅ=b.¹¤ºÅ
group by a.¹¤ºÅ
SQL code:
1> select * from ±í1;
2> go
¹¤ºÅ |ÐÕÃû
-----------|----------
1|Ëν
2|¬¿¡Òå
(2 rows
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@str = |108||203|
²éÕÒ·µ»Ø½á¹ûstr = 108 Ö»·µ»ØµÚÒ»¸ö ÆäËüµÄ¶¼¸Éµô
SQL code:
declare @str varchar(100)
set @str = '|108||203|'
select substring(@str,2,charindex('|',stuff(@str,1,1,''))-1)
......