MSSQL中如何选择一行中最小的时间？

一张表，字段分为id,time1,time2,time3,time4,time5 

请问我应该如何选择ID为1的那条记录中time时间最小的值呢？

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UP!

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[code=SQL][/code]select min(t) from 
(select time1 as t from t1 where id=1 union all
select time2 as t from t1 where id=1 union all
select time3 as t from t1 where id=1 union all
select time4 as t from t1 where id=1 union all
select time5 as t from t1 where id=1 ) as tb

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[code=SQL][/code] select min(t) from 
(select time1 as t from t1 where id=1 union all
select time2 as t from t1 where id=1 union all
select time3 as t from t1 where id=1 union all
select time4 as t from t1 where id=1 union all
select time5 as t from t1 where id=1 ) as tb

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用动态连接一下字符串

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晕。。。这么多的SQL语句啊。。那执行起来所花的时候是不是很多啊。。。

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SQL code:
----------------------------------------------------------------
-- Author :SQL77(只为思齐老)
-- Date :2010-01-26 19:29:35
-- Version:
-- Microsoft SQL Server 2000 - 8.00.194 (Intel X86)
-- Aug 6 2000 00:57:48
-- Copyright (c) 1988-2000 Microsoft Corporation
-- Desktop Engine on Windows NT 5.1 (Build 2600: Service Pack 3)
--
----------------------------------------------------------------
--> 测试数据：#TB
if object_id('TB') is not null drop table TB
go
cr