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select * from table where '123456789' like '%'+×ֶαí+'%'


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SQL code:
select * from table where instr('123456789' , ×ֶαí)




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http://topic.csdn.net/u/20090501/15/7548d251-aec2-4975-a9bf-ca09a5551ba5.html

select * from table where ×ֶαí like '%123456789%'



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MySQLConnection DBConn;
DBConn = new MySQLConnection(new MySQLConnectionString("localhost" , "admin" , "root" , "123456" , 3306).AsString);
DBConn.Open(); ......
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