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select * from table where '123456789' like '%'+×ֶαí+'%'
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SQL code:
select * from table where instr('123456789' , ×ֶαí)
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http://topic.csdn.net/u/20090501/15/7548d251-aec2-4975-a9bf-ca09a5551ba5.html
select * from table where ×ֶαí like '%123456789%'
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