PHP中，输入周次，得出该周日期 - PHP / 基础编程

如题，请问如何做？

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我是这么写的，年初数加上周的天数，可以得到这周某一天的日期，至于这周星期一到星期天是几号到几号，我还没想到。
  不知道楼主的意思我理解的对不对。我是新手。

PHP code:

<?php
date_default_timezone_set('Asia/Shanghai');

$date1 = strtotime('2010-01-01');
$date2 = 1*7*24*60*60; //第一个“1”就是你要填写第几周
$date3 = $date1+$date2;
echo date('Y-m-d',$date3);

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从网上找来的,稍微做了一下修改

PHP code:

function GetWeekDate ($week, $year) {
$timestamp = mktime(0, 0, 0, 1, 1, $year);
$dayofweek = date("w", $timestamp);
if ($week != 1) {
$distance = ($week - 1) * 7 - $dayofweek + 1;
$passed_seconds = $distance * 86400;
$timestamp += $passed_seconds;
$firt_date_of_week = date("Ymd", $timestamp);
}
if ($week == 1) {
$distance = 7 - $dayofweek;
} else {
$distance = 6;
$timestamp += $distance * 86400;
$last_date_of_week = date("Ymd", $timestamp);
}
echo $year . '年的第' . $week . '星期的星期一是：' . $firt_date_of_week . '，星期天是' . $last_date_of_week;
}
GetWeekDate (3, 2010);



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