fenshu±íÖеÄ×Ö¶ÎΪ£ºid,user,fs 7Ìõ¼Ç¼ÈçÏ£º 0¡¡ÕÅÈý¡¡10 1¡¡ÀîËÄ¡¡20 2¡¡ÍõÎå¡¡60 3¡¡Ð¡¶þ¡¡30 4¡¡ºÇºÇ¡¡40 5¡¡Ð¡»¨¡¡80 6¡¡Ð¡°×¡¡40 °´fs½µÐòÅÅÐòºóµÃµ½£º 5¡¡Ð¡»¨¡¡80 2¡¡ÍõÎå¡¡60 4¡¡ºÇºÇ¡¡40 6¡¡Ð¡°×¡¡40 3¡¡Ð¡¶þ¡¡30 1¡¡ÀîËÄ¡¡20 0¡¡ÕÅÈý¡¡10 ÈçºÎȡΪfsΪ40µÄ¼Ç¼½µÐòÅÅÁдÎÐò¼´3»ò4 SQL code: select b.* (select a.*,(select count(*)+1 from fenshu where fs>a.fs) as row_num from fenshu a) b order by b.row_num desc;
ÀïÃæµÄaºÍbÖ¸µÄÊÇʲô£¿ÈçºÎÊä³öÃû´Î£¿ a,bÊDZíµÄ±ðÃû£¬×Ö¶Îrow_num¾ÍÊÇÃû´ÎÁË Èý¸öselect·Ö¿ªÔõôд£¿ SELECT a.id,a.user,a.fs,count(b.id) from t1 a left join t1 b on (a.fs <b.fs) or (a.fs=b.fs and a.id>=b.id) group by a.id,a.user,a.fs order by a.fs desc MySQLÖеÄROWNUMµÄʵÏÖ http://blog.csdn.net/ACMAIN_CHM/archive/2009/04/20/4095531.aspx