一个简单的表单提交，插入数据库操作！
错误如下：
Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in E:\wamp\www\Admin\wnewsave.php on line 66
表：NOTICES
结构：
id name content datetime
noticesadd.php
PHP code:
<table width="100%" border="0" align="center" cellpadding="0" cellspacing="0">
<form name="myform" method="post" action="wnewsave.php?action=notices_add">
<tr>
<td height="20" colspan="2"> </td>
</tr>
<tr>
<td width="20%" height="25" align="right">公告标题：</td>
<td width="1081"> <input name="n_title" type="text" id="n_title" size="30" maxlength="100"></td>
</tr>
<tr>
<td height="25" align="right">公告内容：</td>
<td> <textarea name="n_content" cols="50" rows="6" id="n_content"></textarea></td>
</tr>
<tr>
<td height="25" align="right">&n
