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ÓÐÒ»¸ö±íAA
name  tj
1    a
1    b
1    c
2    a
2    d
3    b
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SQL code:
select name from
(
select distinct name from aa where tj ='a'
union all
select distinct name from aa where tj ='b'
) t
group by name having count(1) = 2


SQL code:

select * from AA where tj='a' and tj='c'



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SQL codeselect*from AAwhere tj='a'and tj='c'

Àí½â錯誤.´ó烏龜Õý½â.

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SQL codeselect namefrom
(selectdistinct namefrom aawhere tj='a'unionallselectdistinct namefrom aawhere tj='b'
) tgroupby namehavingcount(1)=2


up

SQL code:
create table aa(name int, tj varchar(10))
insert into aa values(1 , 'a')
insert into aa values(1 , 'b')
insert into aa values(1 , 'c')
ins


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001          Æ·ÖÖ1&n ......

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¿Í»§±àºÅ    ¿Í»§ÏúÊÛ×ܶî
aa            200
bb            300
cc            ......

Çë½ÌÒ»¸öSQLÓ¦ÓÃÎÊÌâ

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ÎÒÏëÎʵÄSQLÊÇ·ñ¿ÉÒÔÔÚ²éѯÓï¾äÒ»½áÊøºó£¬ÔÙ×Ô¶¯Ô ......

Çó×ésqlÓï¾ä(a+b)=a

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a  b
10  7
(a-b)=a
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SQL code:
update a set a=a-b


SQL code:
-->Title:Generating test data
-->Author ......

ÇóÕâ¾äSqlÈçºÎÀí½â

create table [¿Í»§ÁªÏµ±í]([¿Í»§±àºÅ] varchar(2),[ÁªÏµÈÕÆÚ] datetime,[ÁªÏµÄÚÈÝ] int)
insert [¿Í»§ÁªÏµ±í]
select 'aa','2009/01/01',111 union all
select 'bb','2009/02 ......
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