求SQL一条语句的解决方法

比如 我有一个表 bumen

里面 有一个列  quanxian
id  name  quanxian

1    a    001;002;003;
2    b    002;003;
3    c    003;004;
4    d    001;002;003;

我的意思是把quanxian列中含有002的数据取出来；显示在gridview上？
请大侠们帮忙！ 

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select * from tumen where quanxian like '%002%'

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select * from tumen where quanxian like '%002%'
select * from tumen where charindex('002',quanxian) > 0

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SQL code:

if object_id('ta') is not null drop table ta
go
create table ta(id int, name varchar(1), quanxian varchar(20))
insert into ta select
1, 'a', '001;002;003;' union all select
2, 'b', '002;003;' union all select
3, 'c', '003;004;' union all select
4, 'd', '001;002;003;'

select * from ta
where charindex(';002;',';'+quanxian)>0

id name quanxian
----------- ---- --------------------
1 a 001;002;003;
2 b 002;003;
4 d 001;002;003;

(3 行受影响)

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SQL code:
select * from tumen where charindex(','+'002'+',',','+quanxian+',') >