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1 null
2 null
3 null
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1 2008-1-6
1 2004-5-3
2 2005-5-6
3 2003-5-9
3 2001-2-3
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2 2005-5-6
3 2001-2-3£¨×îС£©
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SQL code:
update a set
ʱ¼ä = b.ʱ¼ä
from tb1 as a
join tb2 as b
on a.¿¨ºÅ= b.¿¨ºÅ
where not exists(select * from tb2
where ¿¨ºÅ=b.¿¨ºÅ and ʱ¼ä> b.ʱ¼ä)
b ÄÚ±í
1 2007 1 2007
1 2008 1 2008
1 2004 1 2004
2007 = <all N
2008 = <all
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