sqlÓï¾ä
1.
User±íÓÃÓڼǼÓû§Ïà¹ØÐÅÏ¢, Photo±íÓÃÓڼǼÓû§µÄÕÕÆ¬ÐÅÏ¢, Á½¸ö±íµÄ¶¨ÒåÈçÏÂ:
CREATE TABLE User( --Óû§ÐÅÏ¢±í
UserId bigint, --Óû§Î¨Ò»id
Account varchar(30) --Óû§Î¨Ò»ÕʺÅ
);
CREATE TABLE Photo( --ÕÕÆ¬ÐÅÏ¢±í
PhotoId bigint, --ÕÕÆ¬Î¨Ò»id
UserId bigint, --ÕÕÆ¬ËùÊôÓû§id
AccessCount int, --·ÃÎÊ´ÎÊý
Size bigint --ÕÕÆ¬Îļþʵ¼Ê´óС
)
1) Çë¸ø³öSQL´òÓ¡ÕʺÅΪ"dragon"µÄÓû§·ÃÎÊ´ÎÊý×î¶àµÄ5ÕÅÕÕÆ¬µÄid;
2) ¸ø³öSQL´òÓ¡ÓµÓÐ×ܵÄÕÕÆ¬Îļþ´óС(total_size)×î¶àµÄǰ10ÃûÓû§µÄid, ²¢¸ù¾Ýtotal_size½µÐòÅÅÁÐ
3) ΪÓÅ»¯ÉÏÃæÁ½¸ö²éѯ, ÐèÒªÔÚUserºÍPhoto±íÉϽ¨Á¢Ê²Ã´ÑùµÄË÷Òý?
2.
Êý¾Ý¿âÖÐÓбíUser(id, name, age):
±íÖÐÊý¾Ý¿ÉÄÜ»áÊÇÒÔÏÂÐÎʽ:
id name age
001 ÕÅÈý 56
002 ÀîËÄ 25
003 ÍõÎå 56
004 ÕÔÁù 21
005 Ç®Æß 39
006 Ëï°Ë 56
..............
ÓÉÓÚÈËÔ±ÄêÁäÓпÉÄÜÏàµÈ, Çëд³öSQLÓï¾ä, ÓÃÓÚ²éѯage×î´óµÄÈËÔ±ÖÐ, id×îСµÄÒ»¸ö¼Ç¼
1.
select photoid from(
select b.photoid,row_number()over(order by accesscount desc)rn
from user a,photo b
where a.user_id=b.user_id
and a.account='dragon')
where rn <=5
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1. 2)
select user_id,s from(
select user_id
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