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002 b 
003 c 

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  001 2 2009-02-26 
  002 3 2009-01-13 
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  Óû§±àÂë Óû§Ãû³Æ ±¾ÆÚÖ¸Êý 
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SQL code:
SELECT A.Óû§±àÂë,Óû§Ãû³Æ, ±¾ÆÚÖ¸Êý =COUNT(*)
from YH A,YS B
WHERE A.Óû§±àÂë=B.Óû§±àÂë
GROUP BY A.Óû§±àÂë,Óû§Ãû³Æ


SQL code:
select
yh.*,
isnull(ys.±¾ÆÚÖ¸Êý,0) as ±¾ÆÚÖ¸Êý
from
yh
left join
ys
on yh.Óû§±àÂë =ys.Óû§±àÂë
and not exists(select 1 from ys t where t.Óû§±àÂë=ys.Óû§±àÂë and t.³­±íʱ¼ä>ys.³­±íʱ¼ä)


select c.*,t.³­±íʱ¼ä
from yb c,(
select *
from ys a
where not exists (select 1 
from ys b
where a.Óû§±àÂë=b.Óû§±àÂë and a.³¬±êʱ¼ä<b.³­±íʱ


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