ÏÖÓÐÒ»¸ö±í£º ²¿ÃÅ ÏîÄ¿ ÏîÄ¿Ã÷ϸ ×ʽð·½Ïò A T R Ö§³ö B Y E Ö§³ö A W Q Ö§³ö C L K ÊÕÈë A M N ÊÕÈë
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group by ²¿ÃÅ ,×ʽð·½Ïò ÎÒÊÔÊÔ¡£ SQL code: --> Éú³É²âÊÔÊý¾Ý±í: [tb] IF OBJECT_ID('[tb]') IS NOT NULL DROP TABLE [tb] GO CREATE TABLE [tb] ([²¿ÃÅ] [nvarchar](10),[ÏîÄ¿] [nvarchar](10),[ÏîÄ¿Ã÷ϸ] [nvarchar](10),[×ʽð·½Ïò] [nvarchar](10)) INSERT INTO [tb] SELECT 'A','T','R','Ö§³ö' UNION ALL SELECT 'B','Y','E','Ö§³ö' UNION ALL SELECT 'A','W','Q','Ö§³ö' UNION ALL SELECT 'C','L','K','ÊÕÈë' UNION ALL SELECT 'A','M','N','ÊÕÈë'
ÓÐ2¸öÊý¾Ý±íAÓëB£¬ÈçºÎ²¹³äAÖÐûÓÐ,BÖÐÓеÄÊý¾Ý£¬Ê¹A±íÊý¾ÝÍêÕû£¿ÇëдϾßÌåÔ´´úÂë SQL code: insert A select * from A right join B on A.key=b.key where A.key is null