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  ²¿ÃÅ ÏîÄ¿ ÏîÄ¿Ã÷ϸ ×ʽð·½Ïò  
  A T R Ö§³ö
  B Y E Ö§³ö
  A W Q Ö§³ö
  C L K ÊÕÈë
  A M N ÊÕÈë  

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SQL code:
select count(distinct ²¿ÃÅ)
from [Table]
group by ²¿ÃÅ,×ʽð·½Ïò


group by ²¿ÃÅ ,×ʽð·½Ïò

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SQL code:
--> Éú³É²âÊÔÊý¾Ý±í: [tb]
IF OBJECT_ID('[tb]') IS NOT NULL
DROP TABLE [tb]
GO
CREATE TABLE [tb] ([²¿ÃÅ] [nvarchar](10),[ÏîÄ¿] [nvarchar](10),[ÏîÄ¿Ã÷ϸ] [nvarchar](10),[×ʽð·½Ïò] [nvarchar](10))
INSERT INTO [tb]
SELECT 'A','T','R','Ö§³ö' UNION ALL
SELECT 'B','Y','E','Ö§³ö' UNION ALL
SELECT 'A','W','Q','Ö§³ö' UNION ALL
SELECT 'C','L','K','ÊÕÈë' UNION ALL
SELECT 'A','M','N','ÊÕÈë'

SELECT count(distinct ²¿ÃÅ+×ʽð·½Ïò) from [tb]

-->SQL²éѯÈçÏÂ:
/*
-----------
4

(1 ÐÐÊÜÓ°Ïì)
*/


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Êý¾ÝÒÔxml¸ñʽ·µ»Ø - MS-SQL Server / Ó¦ÓÃʵÀý

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SQL ÎÊÌâ - MS-SQL Server / »ù´¡Àà

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insert A select * from A right join B on A.key=b.key where A.key is null


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