ÇóÒ»¾äSQL - MS-SQL Server / »ù´¡Àà
ÐÕÃû ÈÕÆÚ Öµ
ÕÅÈý 2009-1-1 10
ÕÅÈý 2009-2-1 100
ÀîËÄ 2008-12-1 22
ÀîËÄ 2009-1-1 135
ÎÒÏë»ñµÃËùÓÐÈË ÈÕÆÚ×îСµÄÖµ ²¢ºÏ¼Æ
¼´ÕÅÈýµÄ10¼ÓÉÏÀîËĵÄ22 »ñµÃ×îºó½á¹ûÊÇ32
SQL code:
select ÐÕÃû,min(ÈÕÆÚ) ÈÕÆÚ,ºÏ¼Æ=sum(Öµ) from tb group by ÐÕÃû
SQL code:
--> Éú³É²âÊÔÊý¾Ý±í: [tb]
IF OBJECT_ID('[tb]') IS NOT NULL
DROP TABLE [tb]
GO
CREATE TABLE [tb] ([ÐÕÃû] [nvarchar](10),[ÈÕÆÚ] [datetime],[Öµ] [int])
INSERT INTO [tb]
SELECT 'ÕÅÈý','2009-1-1','10' UNION ALL
SELECT 'ÕÅÈý','2009-2-1','100' UNION ALL
SELECT 'ÀîËÄ','2008-12-1','22' UNION ALL
SELECT 'ÀîËÄ','2009-1-1','135'
-->SQL²éѯÈçÏÂ:
SELECT ÐÕÃû,MIN(ÈÕÆÚ) ÈÕÆÚ,ºÏ¼Æ=SUM(Öµ) from tb GROUP BY ÐÕÃû
/*
ÐÕÃû ÈÕÆÚ ºÏ¼Æ
---------- ----------------------- -----------
ÀîËÄ 2008-12-01 00:00:00.000 157
ÕÅÈý 2009-01-01 00:00:00.000 110
(2 ÐÐÊÜÓ°Ïì)
*/
SQL code:
select sum(Öµ) from table_name a join (select ÐÕÃû,min(ÈÕÆÚ) ÈÕÆÚ from table_name group by ÐÕÃû) b on a.ÐÕÃû=b.ÐÕÃû and a.ÈÕÆÚ=b.ÈÕÆÚ
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101 32.3 0 ......
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COL1 COL2 COL2 COL4 COL5
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