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id name parentID
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1 books 0
2 software 0
3 Philosophy 1
4 Confucianism 3
5 Utilities 2
6 Literature 1
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Books - Philosophy
Books - Philosophy - Confucianism
Books - Literature
Software - Utilities
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SQL code:
SQL 2000ºÍ2005 Ê÷Ðεݹ鷨С»ã×Ü ÊÕ²Ø
/*
* ±¾ÈËÔÚǰ±²»ù´¡ÉÏÕûÀí¶ø³É
*ÄÚÈÝÊǹØÓڵݹé²éѯµÄ 2000 ºÍ2005²»Í¬µÄÓ÷¨
*/
--²âÊÔÊý¾Ý
if OBJECT_ID('tb') is not null
drop table tb
go
CREATE TABLE tb(ID char(3),PID char(3),Name nvarchar(10))
INSERT tb SELECT '001',NULL ,'ɽ¶«Ê¡'
UNION ALL SELECT '002','001','ÑĮ̀ÊÐ'
UNION ALL SELECT '004','002','ÕÐÔ¶ÊÐ'
UNION ALL SELECT '003','001','ÇൺÊÐ'
UNION ALL SELECT '005',NULL ,'ËÄ»áÊÐ'
UNION ALL SELECT '006','005','ÇåÔ¶ÊÐ'
UNION ALL SELECT '007','006','С·ÖÊÐ'
GO
--2000µÄ·½·¨
--²éѯָ¶¨½Úµã¼°ÆäËùÓÐ×Ó½ÚµãµÄº¯Êý
CREATE FUNCTION f_Cid(@ID char(3))
RETURNS @t_Level TABLE(ID char(3),Level int)
AS
BEGIN
declare @Level int
set @level=1
insert @t_level select @id,@level
while @@rowcount>0
begin
set @level=@level+1
insert @t_Level select tb.id,@level
from tb join @t_level t on tb.pid=t.id
where t.level+1=@level
end
return
end
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select ²¿ÃÅ,ÐÕÃû from tb
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----------------------------------------------------------------------------------------------
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select o_customer,o_price from orders having o_price >=avg(o_price)
select o_customer,o_price from orders where o_price >=(select avg(o_price) from orders)
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°´ÏÂÃæÖ´ÐÐÏÂÀ´ Ö»Óбí×îºóÒ»ÐмÓÉÏÁË 'aaa' ......