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sql ¼òµ¥²éѯÇóÖú - MS-SQL Server / ÒÉÄÑÎÊÌâ

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no name
-----------
x1 wade
2d james
pk kobe
aa KG


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no name no name
-------------------------
x1 wade 2d james
px kobe aa KG



SQL code:
create table tb (no varchar(5),name varchar(10))
insert tb
select 'x1', 'wade' union all
select '2d', 'james' union all
select 'pk', 'kobe' union all
select 'aa', 'KG'

select max(no1) no ,max(name1) name,max(no2) no ,max(name2) name from
(
select (row_number()over(order by getdate())-1)/2 rn,
(case when row_number()over(order by getdate())%2=1 then no else '' end) no1,
(case when row_number()over(order by getdate())%2=1 then name else '' end) name1,
(case when row_number()over(order by getdate())%2=0 then no else '' end) no2,
(case when row_number()over(order by getdate())%2=0 then name else '' end) name2
from tb
) t
group by rn

/*
no name no name
----- ---------- ----- ----------
x1 wade 2d james
pk kobe aa KG

£¨ËùÓ°ÏìµÄÐÐÊýΪ 2 ÐУ©

*/



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select * , id=identity(int,1,1) into tmp from tb


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select o_customer,o_price from orders having o_price >=avg(o_price)
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