xml配置的小问题
struts.xml小问题
<global-exception-mappings>
<exception-mapping exception="com.ssh.common.core.ProjectException" result="exception" />
</global-exception-mappings>
<global-results>
<result name="exception">
<param name="location">/common/error.jsp </param>
</result>
<result name="login">/login.jsp </result>
</global-results>
web.xml问题
<!-- 加载spring的配置文件 -->
<context-param>
<param-name>contextConfigLocation </param-name>
<param-value>/WEB-INF/applicationContext-*.xml </param-value>
</context-param>
<!-- spring 提供的字符串过滤器 -->
<filter>
<filter-name>Spring character encoding filter </filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter </filter-class>
<init-param>
<param-name>encoding </param-name>
<param-value>UTF-8 </param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>Sp
相关问答:
从数据库中查询一张表的数据
select 部门,姓名 from tb
如何才能生成下面的xml格式文件
<folder state="unchecked" label="全部">
<folder state="unchecked" isBra ......
<?xml version="1.0"?>
<root>
<status>433</status>
<msg>这个是汉字</msg>
<serialno>123</serialno>
</root>
如何用ASP读取 status值 ......
<?xml version="1.0" encoding="utf-8" ?>
- <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical&q ......
Private Sub Command1_Click()
Dim MyString() As String
Open "a.xml" For Binary As #1 ' 打开刚创建的文件。
ReDim MyString(LOF(1) - 1)
Put #1, , MyRecord ' 读入所有字符到变量中 ......
<?xml version="1.0" encoding="utf-8" ?>
<HuiSin>
<admin>100,100</admin>
<user>200,200</user>
怎样在这里添加一个新的呢?
< ......