返回如下xml字符串：
<?xml version="1.0" encoding="utf-8" ?>
<DeliverMsg xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="igw.zsdx.com">
<returncode>0 </returncode>
<msg/>
<mos>
<MO>
<aaa>3150 </aaa>
<bbb>1182760 </bbb>
<ccc>07608888888 </ccc>
</MO>
<MO>
<aaa>3151 </aaa>
<bbb>1182760 </bbb>
<ccc>07608888888 </ccc>
</MO>
<MO>
<aaa>123 </aaa>
<bbb>118276039 </bbb>
<ccc>07608888888 </ccc>
</MO>
</mos>
</DeliverMsg>
请教，如何获取各MO下aaa等属性的值？
XmlDocument doc = new XmlDocument();
doc.Load("xml");
doc.SelectNodes("/DeliverMsg/mos/Mo");
下面代码是在winform开发环境下.
C# code
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