xslt解析xml文件 谁个帮忙 - Web 开发 / XML/SOAP
projects.xml
XML code:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="projects.xsl"?>
<projects>
<project>
<Name>Project 1</Name>
</project>
<project>
<Name>Project 2</Name>
</project>
<project>
<Name>Project 3</Name>
</project>
<project>
<Name>Project 4</Name>
</project>
<project>
<Name>Project 5</Name>
</project>
<project>
<Name>Project 6</Name>
</project>
<project>
<Name>Project 7</Name>
</project>
<project>
<Name>Project 8</Name>
</project>
<project>
<Name>Project 9</Name>
</project>
</projects>
我现在需要对projects文件遍历,需要每4条数据一组显示在页面上,如果projects.xml文件中project不超过足8个,则以空白project补充 超过8个project只显示前8个project数据
XML code:
<div class="panel">
<xsl:
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package com.javabean.xml;
import java.net.MalformedURLException;
import java.net.URL;
import org.dom4j.io.SAXReader;
import org.dom4j.Attribute;
import org.dom4j.Document;
import org.dom4j.Docum ......
String strXML="<all><student><name>伟哥</name><sex>男</sex><age>27</age></student><student><name>qiaoqiao</name><sex> ......