SELECT g.rid, room_no, planed_count,cc from
    (SELECT rid,room_no, planed_count from YC_HOTEL_ROOM_T ) r
left join
    (SELECT rid,count(*) cc  from  YC_GUEST_INFO_T group by rid ) g
ON   r.rid = g.rid  WHERE planed_count<>cc ......

select ks.login_name,ks.exam_name,ks.start_time,ks.end_time,cj.score
from (
     select u.user_id,u.login_name,e.* from  cphrms.EXAM_USER eu, cphrms.users u, cphrms.exam_info e
     where eu.user_id = u.user_id and eu.exam_id = e.exam_id
) ks
left join  
(select t.exam_id, t.user_id, sum(t.score) as score  from cphrms.user_answer t group by t.exam_id, t.user_id) cj
on
   ks.user_id = cj.user_id and ks.exam_id=cj.exam_id 
where ks.login_name = '19901' 
order by start_time ......

从Table 表中取出第 m 条到第 n 条的记录：(Not In 版本)
SELECT TOP n-m+1 *
  from Table
  WHERE (id NOT IN (SELECT TOP m-1 id from Table ))
--从TABLE表中取出第m到n条记录 (Exists版本)
SELECT TOP n-m+1 * from TABLE AS a WHERE Not Exists
(Select * from (Select Top m-1 * from TABLE order by id) b Where b.id=a.id )
Order by id
--m为上标，n为下标,例如取出第8到12条记录,m=8,n=12,Table为表名
Select Top n-m+1 * from Table
Where Id>(Select Max(Id) from
(Select Top m-1 Id from Table Order By Id Asc) Temp)
Order By Id Asc
1.  Select Top n-m+1 * from Table Where Id>(Select Top m-1 Id from Table Order By Id Asc) Order By Id Asc
2.  SQL Server 2005 中可以用 ROW_NUMBER（） OVER（）配合取分页数据了。
DECLARE @StartRow INT
DECLARE @PageSize INT
SET ROWCOUNT 0
SET @StartRow = 100
SET @PageSize = 10
SELECT * from
(
  SELECT ROW_NUMBER() OVER (ORDER BY Name) AS RowNumber,* from Person
) AS A WHERE A.RowNumber BETWEEN @StartRow + 1 AND @StartRow + ......

Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
问题：
1、查询“001”课程比“002”课程成绩高的所有学生的学号；
  select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
  from SC where C#='002') b
  where a.score>b.score and a.s#=b.s#;
2、查询平均成绩大于60分的同学的学号和平均成绩；
    select S#,avg(score)
    from sc
    group by S# having avg(score) >60;
3、查询所有同学的学号、姓名、选课数、总成绩；
  select Student.S#,Student.Sname,count(SC.C#),sum(score)
  from Student left Outer join SC on Student.S#=SC.S#
  group by Student.S#,Sname
4、查询姓“李”的老师的个数；
  select count(distinct(Tname))
  from Teacher
  where Tname like '李%';
5、查询没学过“叶平”老师课的同学的学号、姓名；
    select Student.S#,Stu ......

Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
问题：
1、查询“001”课程比“002”课程成绩高的所有学生的学号；
  select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
  from SC where C#='002') b
  where a.score>b.score and a.s#=b.s#;
2、查询平均成绩大于60分的同学的学号和平均成绩；
    select S#,avg(score)
    from sc
    group by S# having avg(score) >60;
3、查询所有同学的学号、姓名、选课数、总成绩；
  select Student.S#,Student.Sname,count(SC.C#),sum(score)
  from Student left Outer join SC on Student.S#=SC.S#
  group by Student.S#,Sname
4、查询姓“李”的老师的个数；
  select count(distinct(Tname))
  from Teacher
  where Tname like '李%';
5、查询没学过“叶平”老师课的同学的学号、姓名；
    select Student.S#,Stu ......

追加：row_number, rank, dese_rank, ntile
1. row_number: 为查询出来的每一行记录生成一个序号。
SELECT row_number() OVER(ORDER BY field) AS row_n
from tablename;
分页查询：
with t_towtable
as (select row_number over(order by field1) as row_number from tb)
select * from t_rowtable where row_number > 1 and row_number > 4 order by field1;
ROW_NUMBER() OVER([<partition_by_caluse>] <order_by_clause>);
2. rank: 返回结果集的分区内每行的排名：
RANK() OVER([<partition_by_caluse_按照某个字段分区>]<order_by_clause_排序>);
Examples：
WITH CustomerSum AS
(SELECT CustomerID, SUM(totalDue) AS total
  from sales GROUP BY CustomerID)
SELECT * RANK() OVER (ORDER BY total DESC) AS RANK
from CustomerSum
3. dense_rank: 顺序排序（生成的序号是连续的）。
4. ntile：取前多少个名次的排名的行。
SELECT SalesID, NTILE(1000) OVER(ORDER BY CustomerID) AS NTile
from Sales
桶数的计算：
if(记录数%桶数 == 0)
      每桶记录数都为记数总数/桶数 ......