在oracle中关于树的sql
表task，字段id_，name_
id_的数据如下形式：
1
1.1
1.1.1
1.1.1.2
1.2
1.2.1
...
10
10.1
10.1.1
10.2.1
10.2.1.1
10.2.1.1.1
10.2.1.1.2
.......
注：“.”标识父子的关系。
现在通过id_查询树结构的效果，并且知道此节点是否为叶子节点leaf。。？
语句如下：
select
id_ ,
name_ ,
(select count(id_) from task where t.id_= substr(id_,0,INSTR((id_),'.',-1)-1) ) as leaf,connect_by_isleaf from task t
start with t.id_ ='5' connect by prior
t.id_= substr(t.id_,0,INSTR((t.id_),'.',-1)-1) order by t.id_
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