Python Ascii to bcd bcd to Ascii
ÔÚÍøÉÏËѲ»µ½¹ØÓÚ Ascii ºÍ bcd»¥Ïàת»¯µÄÎÄÕ£¬ÓÚÊÇ×Ô¼ºÐ´ÁËÒ»¸ö£¬ºÍ´ó¼Ò·ÖÏíÏ¡£
ûÓп¼Âǵ½Ð§ÂÊ£¬Äܹ»ÓÅ»¯µÄµØ·½Íû´ó¼ÒÌá³ö
"""
AscII×Ö·ûת»»ÎªBCD×Ö·û
"""
def asc2bcd(inAsc, pad_L0_R1 = 0):
#È«²¿×ª»»Îª´óд£¬ÎªºóÃæµÄת»»Ìṩ·½±ã
inAsc = inAsc.upper()
print inAsc
#ÅжÏÈç¹û·ÇżÊý¸ö×Ö·ûʱ£¬×ó²¹0£¬»¹ÊÇÓÒ²¹0
import copy
if(len(inAsc)%2 == 1):
if(pad_L0_R1 == 0):
inAsc = copy.copy('0'+inAsc)
if(pad_L0_R1 == 1):
inAsc = copy.copy(inAsc+'0')
#¼ì²âÊäÈëµÄp×Ö·û´®ÖÐÊÇ·ñ¶¼Îª0-9 a-f A-F ÖеÄ×Ö·û
for i in inAsc:
if ((i>='0')and(i<='9')):
continue;
if ((i>='A')and(i<='F')):
continue
print "ÊäÈëÁË·Ç0-9 a-f A-F ÖеÄ×Ö·û"
return
a = array.array('B', inAsc)
v = array.array('B','\x00'*1000)
length = 0
b = 0
c = 0
for i in range(0, len(inAsc), 2):
if ((a[i]>=ord('0'))&(a[i]<=ord('9'))):
b = 0x3
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By phidoit@gmail.com
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