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match Match a regular expression pattern to the beginning of a string.
search re.search(pattern, string, flags) flags:re.I re.M re.X re.S re.L re.U
sub Substitute occurrences of a pattern found in a string.
subn Same as sub, but also return the number of substitutions made.
split Split a string by the occurrences of a pattern.
findall Find all occurrences of a pattern in a string.
finditer Return an iterator yielding a match object for each match.
iter = re.finditer("23", "123423523")
for i in iter:
print i.span()
compile ½«Ò»¸öpattern±àÒë³ÉÒ»¸öRegexObject.
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purge Clear the regular expression cache.
escape Backslash all non-alphanumerics in a string.
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(?iLmsux) Ϊpattern¼ÓÈëI,L,M,S,U,X±êÖ¾
(?P<name>) ΪgroupµÄÒ»Ïî¼ÓÈë±ðÃû
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# 035
class Person:
population = 0 #Õâ¸ö±äÁ¿ÊÇÊôÓÚÕû¸öÀàµÄ
def __init__(self, name):
self.name = name
print '³õʼ»¯ %s' % self.name
Person.population += 1
# end of def
def __del__(self):
print '%s says bye.' % self. ......
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filename=raw_input('enter file name:')
f=open(filename,'rb')
f.seek(0,0)
index=0
for i in range(0,16):
print "%3s" % hex(i) ,
print
for i in range(0,16):
print "%-3s" % "#" ,
print
while True:
temp=f.read(1)
if len(temp) == 0:
break
else:
print "%3s" % temp.encode('hex'),
......