Ajax的js封装
function send_request(callback, urladdress, isReturnData){
var xmlhttp = getXMLHttpRequest();
xmlhttp.onreadystatechange = function(){
if (xmlhttp.readyState == 4) {//readystate 为4即数据传输结束
try{
if(xmlhttp.status == 200){
if(isReturnData && isReturnData==true){
callback(xmlhttp.responseText);
}
}else{
callback("抱歉,没找到此页面:"+ urladdress +"");
}
} catch(e){
callback("抱歉,发送请求失败,请重试 " + e);
}
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ajax的列表联动示例
1、 输入域:
请选择省:
<select id="sel1" onchange="return choose(this);">
<option value="">--请选择--</option>
<option value="1">湖南省</option>
&nb ......
ajax弹出提示信息
1、 输入域:
<h2>工具提示</h2>
<hr>
<a href="#" onmouseover="over(0)" onmouseout="out()">物品一</a><br><br>
<a href="#" onmouseover="over(1)" onmouseout="out()">物品二 ......
当用ajax返回多个值的时候,可以用xml,也可以用json
json实例
<html>
<head>
<title>AjaxTest</title>
<script type="text/javascript">
var xmlHttp;
function createXMLHttpRequest()
{
if(window.ActiveXObject)
& ......
项目中想用ajax,于是在网上扒了n多资料,犯了n多错误,从今天上班到现在一直在处理这个问题,终于还是把它解决了。
当我看到页面的ajax显示后,我兴奋异常,为了记录自己学习的ajax历程,也为了让更多的人少走弯路,特写此一文以记之!
废话不说了,为了更好的理解,我重做了一个小的项目,以加深印象 ......
http://www.ajaxlines.com/ajax/stuff/article/using_google_is_ajax_search_api_with_java.php
I was rather depressed over a year ago when Google deprecated their SOAP Search API with their AJAX Search API. Essentially Google was saying that they didn want anyone programmatically accessing Google search ......