《编程珠玑》问题的C实现——2：向量旋转

 #include <stdio.h>
#include <stdlib.h>
#define SIZE 17
void reverse(int start, int end);
int data[SIZE] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17};
int main(void)
{
int i = 5;
reverse(0, i - 1);
reverse(i, SIZE-1);
reverse(0, SIZE-1);
return 0;
}
void reverse(int start, int end)
{
int t, i, mid;;
mid = (end - start) % 2 == 0 ? (end - start) / 2 : (end - start) / 2 +1;
for(i = 0; i < mid; i ++){
t = data[i + start];
data[start + i] = data[end - i];
data[end - i] = t;
}

for(i = start; i <= end; i++)
printf("%d ", data[i]);
putchar('\n');
return;

}