C_运用do
源码：
# include <math.h>
# include <stdio.h> /* 数学函数库 */
int main()
{
/* 用s表示多项式的值，用t表示每一项的值 */
double s, t, x; // 此处用双精度声明变量
int n;
printf("please input x: ");
scanf("%lf", &x); // ％lf 代表用双精度输入
/* 赋初值 */
t = x;
n = 1;
s = x;
/* 进行叠加运算 */
do
{
n = n + 2 ;
t = t * (-x*x)/((float)(n)-1)/(float)(n);
s = s + t;
} while (fabs(t)>=1e-8); // 本来是要大于0,但也可大于一个很小的数即可
printf("sin(%f) = %lf\n", x, s);
return 0;
}
相关文档：
例：#define NELE(a) (sizeof(a) / sizeof(a[0]))
int main() {
char str[] = {'E', 'M', 'C'};
for (int d=-1; d<=(NELE(str)-2);d++)
printf("%c",str[d+1]);
return 0;
}
判断printf（）输出的是什么，结果可能出乎意料，什么也没有输出，原因呢？原因 ......
源码:
# include <stdio.h>
int main()
{
/* 定义一个整数类型的变量，用来存放后面算式的值 */
int logic;
int a = 1;
int b = 2;
int c = 3;
&n ......
源码:
# include <stdio.h>
int main()
{
int i, j, k;
int m, n, p;
i = 8;
j = 10;
k = 12;
/* 自增在操作数之前 */
......
源码:
# include <stdio.h>
int main()
{
int x, y, z, mid, dec;
printf("请任意输入三个整数：\n");
scanf("%d %d %d", &x, & ......
源码:
# include <stdio.h>
int main()
{
int x, y, num1, num2, temp;
printf("请输入两个正整数：\n");
scanf("%d %d", &num1, &num2);
if(num1 < num2)
......
