网上Down的一个单元.自己改了下. unit utCRC32;
interface
uses
Windows,SysUtils,Classes;
const //Crc32表
Crc32Tab: Array[0..$FF] of LongInt =
($00000000, $77073096, $ee0e612c, $990951ba, $076dc419, $706af48f,
$e963a535, $9e6495a3, $0edb8832, $79dcb8a4, $e0d5e91e, $97d2d988,
$09b64c2b, $7eb17cbd, $e7b82d07, $90bf1d91, $1db71064, $6ab020f2,
$f3b97148, $84be41de, $1adad47d, $6ddde4eb, $f4d4b551, $83d385c7,
$136c9856, $646ba8c0, $fd62f97a, $8a65c9ec, $14015c4f, $63066cd9,
$fa0f3d63, $8d080df5, $3b6e20c8, $4c69105e, $d56041e4, $a2677172,
$3c03e4d1, $4b04d447, $d20d85fd, $a50ab56b, $35b5a8fa, $42b2986c,
$dbbbc9d6, $acbcf940, $32d86ce3, $45df5c75, $dcd60dcf, $abd13d59,
$26d930ac, $51de003a, $c8d75180, $bfd06116, $21b4f4b5, $56b3c423,
$cfba9599, $b8bda50f, $2802b89e, $5f058808, $c60cd9b2, $b10be924,
$2f6f7c87, $58684c11, $c1611dab, $b6662d3d, $76dc4190, $01db7106,
$98d220bc, $efd5102a, $71b18589, $06b6b51f, $9fbfe4a5, $e8b8d433,
$7807c9a2, $0f00f934, $9609a88e, $e10e9818, $7f6a0dbb, $086d3d2d,
$91646c97, $e6635c01, $6b6b51f4, $1c6c6162, $856530d8, $f262004e,
$6c0695ed, $1b01a57b, $8208f4c1, $f50fc457, $65b0d9c6, $12b7e950,
$8bbeb8ea, $fcb9887c, $62dd1ddf, $15da2d49, $8cd37cf3, $fbd44c65,
$4db26158, $3ab551ce, $a3bc0074, $d4bb30e2, $4adfa541, $3dd895d7,
$a4d1c46d, $d3d6f4fb, $4369e96a, $346ed9fc, $ad678846, $da60b8d0,
$44042d73, $33031de5, $aa0a4c5f, $dd0d7cc9, $5005713c, $270241aa,
$be0b1010, $c90c2086, $5768b525, $206f85b3, $b966d409, $ce61e49f,
$5edef90e, $29d9c998, $b0d09822, $c7d7a8b4, $59b33d17, $2eb40d81,
$b7bd5c3b, $c0ba6cad, $edb88320, $9abfb3b6, $03b6e20c, $74b1d29a,
$ead54739, $9dd277af, $04db2615, $73dc1683, $e3630b12, $94643b84,
$0d6d6a3e, $7a6a5aa8, $e40ecf0b, $9309ff9d, $0a00ae27, $7d079eb1,
$f00f9344, $8708a3d2, $1e01f268, $6906c2fe, $f762575d, $806567cb,
$196c3671, $6e6b06e7, $fed41b76, $89d32be0, $10da7a5a, $67dd4acc,
在写c++的接口时可以将两个相互引用的类放在两个.h文件中，然后将这个接口翻译到delphi时，放在两个文件里就不可能了。只能放在同一个unit中。并且要将这两个类都放在同一个type下面进行定义，当前面一个类要使用后面一个类时，需要在前面一个类的前面放置一个前置声明，并且前置声明只能是IVariantMap = class;这种格式而� ......
技术交流,DH讲解. 之前照着天书夜读,用Delphi来弄了下循环体,现在就来弄一下条件判断吧.
首先肯定是我们经常看见的IF语句咯. Var
I: Integer;
Begin
I:= 99;
If (I> 0)And (I< 0) Then
Writeln('I>0')
Else
If (I> 10)And (I< 100) Then
Writeln('I>10 and I100');
End.
反汇编出来会是 ......
