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DROP TABLE IF EXISTS `user`;
CREATE TABLE `user` (
  `ID` int(11) NOT NULL auto_increment,
  `NAME` varchar(16) NOT NULL default '',
  `REMARK` varchar(16) NOT NULL default '',
  PRIMARY KEY  (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=24 DEFAULT CHARSET=utf8;
 
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1¡¢»ñÈ¡Óû§ÐÅÏ¢
CREATE DEFINER=`root`@`localhost` PROCEDURE `getUserList`()
BEGIN
  select * from user;
END;
2¡¢Í¨¹ý´«Èë²ÎÊý´´½¨Óû§
CREATE DEFINER=`root`@`localhost` PROCEDURE `insertUser`(nameVar varchar(16),remarkVar varchar(16))
BEGIN
  insert into user(name,remark) values(nameVar,remarkVar);
END;
 
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1¡¢»ñÈ¡Óû§ÐÅÏ¢
Class.forName("org.gjt.mm.mysql.Driver").newInstance();
String url ="jdbc:mysql://localhost/temp?user=root&password=root";
Connection conn = DriverManager.getConnection(url);
String proc = "call getUserList()";
CallableStatement cs = conn.prepareCall(proc);
rs = cs.executeQuery();
while(rs.next()){
    System.out.println(rs.getString(2)+" "+rs.getString(3));
}
2¡¢Í¨¹ý´«Èë²ÎÊý´´½¨Óû§
Connection conn = DriverManager.getConnection(url);
String proc = "call insertUser(?,?)";
CallableStatement cs = conn.prepareCall(proc);
cs.setString(1, "LINRZ");
cs.setString(2, "REMARK");
cs.execute();


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by ZaraByte
How to do a SQL Injection for MYSQL Server 5.0+
1. Find a vulnerable add a ‘ at the end of the site example: news.php?id=1 add a ‘ at the end of the 1 and see if you get a syntax error
2. order by #–
Keep upping the # until you get an error.
3. union all select 1 ......

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