JAVA实现的魔方
未完成 待完善
public class MagicCube {
/**
* 六个面的下标值
* □5
* □□□□ 1234 这四个连体正方形向后顺时针包围 形成筒状 然后 把5和6扣上 就形成正方体
* □6
*/
public static void main(String[] args) {
MagicCube mb = new MagicCube();
int i = 0;
for (Face f : mb.faces) {
int index = 0;
System.out.printf("这是第%d个面:\n",++i);
System.out.printf("%d_%d_%d\n",f.value[index++],f.value[index++],f.value[index++]);
System.out.printf("%d_%d_%d\n",f.value[index++],f.value[index++],f.value[index++]);
System.out.printf("%d_%d_%d\n",f.value[index++],f.value[index++],f.value[index++]);
int[] tmp = f.getColumn(2);
System.out.printf("临时%d_%d_%d\n",tmp[0],tmp[1],tmp[2]);
f.setColumn(2,new int[]{1,2,3});
tmp = f.getColumn(2);
System.out.printf("临时%d_%d_%d\n",tmp[0],tmp[1],tmp[2]);
index = 0;
System.out.printf("修改后%d_%d_%d\n",f.value[index++],f.value[index++],f.value[index++]);
System.out.printf("修改后%d_%d_%d\n",f.value[index++],f.value[index++],f.value[index++]);
System.out.printf("修改后%d_%d_%d\n",f.value[index++],f.value[index++],f.value[index++]);
}
}
public List<Face> faces = new ArrayList<Face>(6);
MagicCube(){
initData();
}
public static final int CURRENT = 1;
public static final int LEFT = 4;
public static final int RIGHT = 2;
public static final int TOP = 5;
public static final int BOTTOM = 6;
public static final int BACK = 3;
class Face{
public int[] value = new int[9];
Face(){}
Face(int[] value){
if(this.value.length == value.length)
this.value = value;
}
int getBackIndex(int side){
switch(side){
case(1): return 3;
case(3): return 1;
case(2): return 4;
case(4): return 2;
case(5): return 6;
case(6): return 5;
default: return -1;
}
}
/**
* 获取当前面的第N�
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* */
public void sort0(double[] a){
for(int i = 0; i < a.length -1; i ++){
......
1.继承：是指先创建一个共有属性的一般类，根据该一般类再创建具有特殊属性的新类，新类继承一般类的状态和行为，并根据需要增加自
己的新的状态和行为
由继承而得到的类� ......
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将以下内容复制Eclipse中运行，随意输入一个用户名，程序会自动计算出注册码，绝对能用！！！
package sun;
import java.io.*;
public class MyEclipseGen {
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