C/C++与Java多维数组，遍历与最大值获取方法！

C/C++
/*
* File: main.cpp
* Author: Vicky
*
* Created on 2010年4月29日, 上午9:46
*/
#include <iostream>
using namespace std;
int maximum(int[], int);
int main(int argc, char** argv) {
// int sg[3][4] = {
int sg[][4] = {
{68, 77, 73, 86},
{87, 96, 78, 89},
{90, 70, 81, 86}
};
int row = (sizeof (sg) / sizeof (int)) / (sizeof (sg[0]) / sizeof (int)); // 3行
int row2 = sizeof (sg[0]) / sizeof (int); // 4列
cout << row << endl; // 3
cout << row2 << endl; // 3
int max = 0;
for (int i = 0; i < row; i++) {
for (int j = 0; j < row2; j++) {
cout << sg[i][j] << "\t";
if(max < sg[i][j])
max = sg[i][j];
}
cout<<endl;
}
cout<<"the max grade is : "<<max<<endl;
cout << "the max grade is : "
<< maximum(&sg[0][0], 3 * 4) //传递第一个元素地址和元素个数
<< endl;
return (EXIT_SUCCESS);
}
int maximum(int grade[], int num) {
int max = 0;
for (int i = 0; i < num; i++)
if (grade[i] > max)
max = grade[i];
return max;
}
输出：
3
4
68        77        73        86       
87        96        78        89       
90        70        81        86       
the max grade is : 96
the max grade is : 96
运行成功（总计时间： 329毫秒）
public class MyTest {
public static void main(String[] args) {
int[][] is = new int[][]{