JavaScript_循环26个英文字母的方法
最近在CSDN上有人问,怎么用JS循环26个英文字母,想都没想,写下以下代码
<script type="text/javascript">
<!--
var character = new Array("A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","X","Y","Z");
for(var i=0;i<25;i++)
{
alert(character[i]);
}
// -->
</script>
后来又看到有另外的解答,很不错,比我的方法巧妙多了,特记录之~~
<script type="text/javascript">
<!--
for(var i=0;i<25;i++)
{
alert(String.fromCharCode((65+i)));
}
// -->
</script>
相关文档:
原文:《Speeding up JavaScript: Working with the DOM》
作者: KeeKim Heng, Google Web Developer
在我们开发互联网富应用(RIA)时,我们经常写一些javascript脚本来修改或者增加页面元素,这些工作最终是DOM——或者说文档对象模型——来完成的,而我们的实现方式会影响到应用的响应速度。
DO ......
删除行
<script>
function del(obj)
{
obj.parentNode.parentNode.removeNode(true);
}
</script>
<body& ......
示例:
- - - - - - - - - - - -
<body>
<input type="button" value="create" onclick="createTr();">
<table border='1' id="t" >
</table>
<input type="button" value="提交" onclick="okss();" />
</body>
<script type="text/javascript">
&nbs ......
reg = /^((((((0[48])|([13579][26])|([2468][048]))00)|([0-9][0-9]((0[48])|([13579][26])|([2468][048]))))-02-29)|(((000[1-9])|(00[1-9][0-9])|(0[1-9][0-9][0-9])|([1-9][0-9][0-9][0-9]))-((((0[13578])|(1[02]))-31)|(((0[1,3-9])|(1[0-2]))-(29|30))|(((0[1-9])|(1[0-2]))-((0[1-9])|(1[0-9])|(2[0-8]))))))$/i; ......