jsp中通过URL地址获取该地址页面中的静态页面
try {
URL url = new URL("http://www.163.com");
InputStream is = url.openStream();
byte[] buffer = new byte[1024];
int i;
while((i = is.read(buffer)) != -1){
System.out.println(new String(buffer,0,i));
}
} catch (Exception e) {
e.printStackTrace();
}
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哪位高手能帮我看下为什么抛出这些异常？
代码
<%@ page language="java" import="java.util.*" contentType="text/html; charset=ISO-8859-1"
pageEncoding="GB2312"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
< ......
public class TaskBean extends Thread{
public TaskBean(){
}
private int percent=0;
private boolean complete=false;
public synchronized&nb ......
目前，最常用的三种动态网页语言有ASP(Active Server Pages),JSP(Java Server Pages),
PHP (Hypertext Preprocessor)。
简 介
ASP全名Active Server & ......
1 Javascript ，设置一个变量，只允许提交一次。
#lt;script language="javascript"#gt;
var checkSubmitFlg = false;
function checkSubmit() {
if (checkSubmitFlg == true) {
return false;
}
checkSubmitFlg = true;
return true;
}
document.ondblcli ......
