jsp中通过URL地址获取该地址页面中的静态页面
try {
URL url = new URL("http://www.163.com");
InputStream is = url.openStream();
byte[] buffer = new byte[1024];
int i;
while((i = is.read(buffer)) != -1){
System.out.println(new String(buffer,0,i));
}
} catch (Exception e) {
e.printStackTrace();
}
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哪位高手能帮我看下为什么抛出这些异常？
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<%@ page language="java" import="java.util.*" contentType="text/html; charset=ISO-8859-1"
pageEncoding="GB2312"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
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JSP/Servlet的编码原理
关键字: jsp, servlet编码
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在 JSP/Servlet 中主要有以下几种设置编码的方式：
pageEncoding ="UTF-8"
contentType = "text/html;charset=UTF-8"
request.setCharacterEncoding("UTF-8")
response.setCharacterEncodin ......
<%@ page language="java" import="java.util.*" pageEncoding="GB2312"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>index</title>
<meta http-equiv="pragma" content="no-cache"&g ......
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<%@page import="java.util.*"%>
<%@page import="java.io.*" %>
<%
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