jsp生成xml文件示例
<％@ page contentType="text/html; charset=gb2312" ％>
<％@ page language="java"％>
<％@ page info="database handler"％>
<％@ page import="java.io.*"％>
<％@ page import="java.lang.*"％>
<％@ page import="java.util.*"％>
<％@ page import="java.sql.*"％>
<％@ page import="javax.servlet.*"％>
<％@ page import="javax.servlet.http.*"％>
<html>
<head>
<meta content="text/html; charset=gb2312" http-equiv="content-type">
</head>
<body>
<％
int i=0;
String temp=null;
String parCode = request.getParameter("code");
String strSql;
try{
Connection con;
Statement stmt;
ResultSet rs;
Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
String url="jdbc:oracle:thin:@192.168.15.248:1521:ycdb";
con=DriverManager.getConnection(url,"webcfcquery","kill859");
//out.println("<center>jdbc连接Oracle数据库</center><br><br>");
stmt=con.createStatement();
strSql = "select account_holder,description from account_holder ";
if(parCode!=null)
strSql += " where account_holder='"+ parCode +"'";
rs=stmt.executeQuery(strSql);
FileOutputStream fo=new FileOutputStream("/usr/local/tomcat/webapps/vehicles/treasurer_voucher.xml");
PrintStream so = new PrintStream(fo);
while(rs.next()){
String col1=rs.getString(1);
String col2=rs.getString(2);
try{
if(i==0){
so.println("<?xml version=\"1.0\" encoding=\"gb2312\" ?>");
so.println("<ufinterface roottag=\"voucher\" billtype=\"gl\" subtype=\"\" replace=\"Y\" receiver=\"1051\" sender=\"1101\" isexchange=\"Y\" filename=\"会计凭证.xml\">");
so.println("<voucher id=\"1234560102\">");
// 注意：这种写法在xml文件显示时会报错，不知道为什么？ so.println("<custcode>"+col1+"</custcode>");
so.print("<custcode>");
if(col2==null) {//如果不判断对象col2是否为null值，那么在进行编码转换时可能会出现NullPointerException异常
so.print(col2);
} else {//因为前面已经定义xml文件的编码显示方式是gb2312，
相关文档：
using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using i_salesDAL;
using i_s ......
//打开某文件(假设web.config在根目录中)
string filename=Server.MapPath("/") + @"WebApplication1\web.config";
XmlDocument xmldoc= new XmlDocument();
xmldoc.Load(filename);
//得到顶层节点列表
......
表结构：
CREATE TABLE `article` (
`id` int(10) unsigned ......
新建xml文件的情况可能不多，但对节点、属性的增删改查会很常见
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(Server.MapPath("data.xml"));
这两句应该很常用的，加载已经存在的xml文档。
XmlNode root;//根节点
root = xmldoc.DocumentElement;//获取根� ......
