Ò׽ؽØÍ¼Èí¼þ¡¢µ¥Îļþ¡¢Ãâ°²×°¡¢´¿ÂÌÉ«¡¢½ö160KB

¼¸¸öɾ³ýÖØ¸´¼Ç¼µÄSQLÓï¾ä

¼¸¸öɾ³ýÖØ¸´¼Ç¼µÄSQLÓï¾ä
2009-03-02 10:08
±ÈÈçÏÖÔÚÓÐÒ»ÈËÔ±±í £¨±íÃû£ºpeosons£©
ÈôÏ뽫ÐÕÃû¡¢Éí·ÝÖ¤ºÅ¡¢×¡Ö·ÕâÈý¸ö×Ö¶ÎÍêÈ«ÏàͬµÄ¼Ç¼²éѯ³öÀ´
select   p1.*   from   persons   p1,persons   p2   where   p1.id<>p2.id   and   p1.cardid   =   p2.cardid   and   p1.pname   =   p2.pname   and   p1.address   =   p2.address
¿ÉÒÔʵÏÖÉÏÊöЧ¹û£®
¼¸¸öɾ³ýÖØ¸´¼Ç¼µÄSQLÓï¾ä
1.ÓÃrowid·½·¨
2.ÓÃgroup by·½·¨
3.ÓÃdistinct·½·¨
1¡£ÓÃrowid·½·¨
¾Ý¾Ýoracle´øµÄrowidÊôÐÔ£¬½øÐÐÅжϣ¬ÊÇ·ñ´æÔÚÖØ¸´,Óï¾äÈçÏ£º
²éÊý¾Ý:
     select * from table1 a where rowid !=(select   max(rowid)
     from table1 b where a.name1=b.name1 and a.name2=b.name2......)
ɾÊý¾Ý£º
    delete   from table1 a where rowid !=(select   max(rowid)
     from table1 b where a.name1=b.name1 and a.name2=b.name2......)
2.group by·½·¨
²éÊý¾Ý:
¡¡¡¡select count(num), max(name) from student --ÁгöÖØ¸´µÄ¼Ç¼Êý£¬²¢ÁгöËûµÄnameÊôÐÔ
¡¡¡¡group by num
¡¡¡¡having count(num) >1 --°´num·Ö×éºóÕÒ³ö±íÖÐnumÁÐÖØ¸´£¬¼´³öÏÖ´ÎÊý´óÓÚÒ»´Î
ɾÊý¾Ý£º
¡¡¡¡delete from student
¡¡¡¡group by num
¡¡¡¡having count(num) >1
¡¡¡¡ÕâÑùµÄ»°¾Í°ÑËùÓÐÖØ¸´µÄ¶¼É¾³ýÁË¡£
3.ÓÃdistinct·½·¨ -¶ÔÓÚСµÄ±í±È½ÏÓÐÓÃ
create table table_new as   select distinct *   from table1 minux
truncate table table1;
insert into table1 select * from table_new;
²éѯ¼°É¾³ýÖØ¸´¼Ç¼µÄ·½·¨´óÈ«
1¡¢²éÕÒ±íÖжàÓàµÄÖØ¸´¼Ç¼£¬Öظ´¼Ç¼ÊǸù¾Ýµ¥¸ö×ֶΣ¨peopleId£©À´ÅжÏ
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
2¡¢É¾³ý±íÖжàÓàµÄÖØ¸´¼Ç¼£¬Öظ´¼Ç¼ÊǸù¾Ýµ¥¸ö×ֶΣ¨peopleId£©À´Åжϣ¬Ö»ÁôÓÐrowid×îСµÄ¼Ç¼
delete from people
where peopleId in (select peopleId from people group by peop


Ïà¹ØÎĵµ£º

MS SQL µÝ¹éº¯Êý


/*
select *,dbo.getDeptTree(id) as DeptTree from sysdept
µÝ¹éº¯Êý
*/
CREATE  function getDeptTree(@NodeId int)
returns varchar(8000)
as
begin
    declare @ret varchar(8000),@ParentId int,@len int
    set @len = 0
  &nb ......

sql(left join,right jion,inner join)Á¬½ÓÏê½â

 ¹ØÓÚsqlÁ¬½Ó
Á¬½ÓÀàÐÍ
ÔÚ¹ØÏµ´úÊýÖУ¬Á¬½ÓÔËËãÊÇÓÉÒ»¸öµÑ¿¨¶û»ýÔËËãºÍÒ»¸öѡȡÔËËã¹¹³ÉµÄ¡£Ê×ÏÈÓõѿ¨¶û»ýÍê³É¶ÔÁ½¸öÊý¾Ý¼¯ºÏµÄ³ËÔËË㣬Ȼºó¶ÔÉú³ÉµÄ½á¹û
¼¯ºÏ½øÐÐѡȡÔËË㣬ȷ±£Ö»°Ñ·Ö±ðÀ´×ÔÁ½¸öÊý¾Ý¼¯ºÏ²¢ÇÒ¾ßÓÐÖØµþ²¿·ÖµÄÐкϲ¢ÔÚÒ»Æð¡£Á¬½ÓµÄÈ«²¿ÒâÒåÔÚÓÚÔÚˮƽ·½ÏòÉϺϲ¢Á½¸öÊý¾Ý¼¯ºÏ£¨Í¨³£ÊÇ±í£©£¬²¢²úÉú
Ò ......

SQL ServerÖÐbitÊý¾ÝÀàÐÍÓ¦ÓÃ

ʹÓùý Access µÄÅóÓѶ¼ÖªµÀ£¬Access ÀïÓиö“ÊÇ/·ñ”Êý¾ÝÀàÐÍ£¬ÔÚ SQL Server ÖУ¬Ã»ÓÐÕâ¸öÃû³Æ£¬¶øÊ¹Óà bit¡£ÔÚʹÓùý³ÌÖÐÓм¸µãÐèҪעÒâµÄ£º
£±¡¢bit Óë SQL Server µÄÕûÐͺÍÊý×ÖÊý¾ÝÏàËÆµÄÊý×ÖÊý¾Ý£¬µ« bit ÁÐÖ»ÄÜ´æ´¢ 0 ºÍ 1¡£
£²¡¢ÔÚ²åÈë¡¢ÐÞ¸Ä bit Êý¾Ýʱ£¬Ê¹Óà 0 »ò 1 £¬¶ø²»ÊÇ false »ò true£¬bit ×Ö¶ ......

SQL »ù±¾½¨±íÓï¾ä

×÷Ϊ±¸Íü°É.ÔÚ»ú·¿ÀïÊäÈëµÄ.
/*CREATE TABLE Student
(Sno CHAR(9) PRIMARY KEY,
 Sname CHAR(20) UNIQUE,
 Ssex CHAR(2),
 Sage SMALLINT,
 Sdept CHAR(20)
);*/
/*CREATE TABLE Course
(Cno CHAR(4) PRIMARY KEY,
 Cname CHAR(40),
 Cpno CHAR(4),
 Credit SMALLINT,
&n ......

SQL Substring

 SQL ÖÐµÄ substring º¯ÊýÊÇÓÃÀ´×¥³öÒ»¸öÀ¸Î»×ÊÁÏÖÐµÄÆäÖÐÒ»²¿·Ö¡£Õâ¸öº¯ÊýµÄÃû³ÆÔÚ²»Í¬µÄ×ÊÁÏ¿âÖв»ÍêȫһÑù£º
MySQL: SUBSTR(), SUBSTRING()
Oracle: SUBSTR()
SQL Server: SUBSTRING()
×î³£Óõ½µÄ·½Ê½ÈçÏ (ÔÚÕâÀïÎÒÃÇÓÃSUBSTR()ΪÀý)£º
SUBSTR(str,pos): ÓÉ<str>ÖУ¬Ñ¡³öËùÓдӵÚ<pos>λÖÿªÊ¼ ......
© 2009 ej38.com All Rights Reserved. ¹ØÓÚE½¡ÍøÁªÏµÎÒÃÇ | Õ¾µãµØÍ¼ | ¸ÓICP±¸09004571ºÅ