SQL XML DELETE
--A. 从存储在非类型化的 xml 变量中的文档中删除节点
DECLARE @myDoc xml
SET @myDoc = '<?Instructions for=TheWC.exe ?>
<Root>
<!-- instructions for the 1st work center -->
<Location LocationID="10" LaborHours="1.1" MachineHours=".2" >
Some text 1
<step>Manufacturing step 1 at this work center</step>
<step>Manufacturing step 2 at this work center</step>
</Location>
</Root>'
SELECT @myDoc
-- delete an attribute
SET @myDoc.modify('
delete /Root/Location/@MachineHours
')
SELECT @myDoc
-- delete an element
SET @myDoc.modify('
delete /Root/Location/step[2]
')
SELECT @myDoc
-- delete text node (in <Location>
SET @myDoc.modify('
delete /Root/Location/text()
')
SELECT @myDoc
-- delete all processing instructions
SET @myDoc.modify('
delete //processing-instruction()
')
SELECT @myDoc
--B. 从存储在非类型化的 xml 列中的文档中删除节点
delete XML DML 语句从存储在列中的文档中删除 <Features> 的第二个子元素。
CREATE TABLE #T (i int, x xml)
go
INSERT INTO #T VALUES(1,'<Root>
<ProductDescription ProductID="1" ProductName="Road Bike">
<Features>
<Warranty>1 year parts and labor</Warranty>
<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>
</Root>')
go
-- verify the contents before delete,query返回Features元素下的所有节点,以XML格式返回
SELECT x.query('//ProductDescription/Features')
from #T
-- delete the second feature
UPDATE #T
SET x.modify('delete /Root/ProductDescription/Features/*[2]')
-- verify the deletion
SELECT x.query(' //ProductDescription/Features')
from #T
DROP TABLE #T
C. 从非类型化的 xml 列中删除节点
create table #T(ProductModelID int primary key,
Instructions xml )
go
insert #T
select ProductModelID, Instructions
from Prod
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现象:
在使用Microsoft SQL Server 2005时,要创建一个登录名,并为该登录名关联了一个数据库,但是在选择“安全对象”选项时,却出现了如题所示的错误。其他信息显示为:执行Transact-SQL语句或批处理时发生了异常(Microsoft.SqlServer.ConnectionInfo)。无法解决 ......
/*
* 主要作用;
* 从xml读取游戏配置信息或保存
*/
using System;
using System.Collections.Generic;
using System.Text;
using System.Windows;
using System.Windows.Forms;
using System.IO;
using System.Xml;
using System.Reflection;
namespace Game
{
class Config
{
Ke ......
TA:
1,WANG
2,ZHANG
4,LI
TB:
1,100
2,200
3,400
1.left join 左连接--以左表为基准,右表中没值的,在结果集中以null值代替。(select * from TA left join TB where TA.ID=TB.ID)
1,WANG,100
2,ZHANG,200
4,NULL
2.right join 右连接--以右表为基准,左表中没值的,在 ......
--处理示例
--示例数据
create table tb(ID int,Name varchar(10),ParentID int)
insert tb select 1,'AAAA' ,0
union all select 2,'BBBB' ,0
union all select 3,'CCCC' ,0
union all select 4,'AAAA-1' ,1
union all select 5,'AAAA-2' ,1
u ......