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1.Ò»µÀSQLÓï¾äÃæÊÔÌ⣬¹ØÓÚgroup by
±íÄÚÈÝ£º
2005-05-09 ʤ
2005-05-09 ʤ
2005-05-09 ¸º
2005-05-09 ¸º
2005-05-10 ʤ
2005-05-10 ¸º
2005-05-10 ¸º
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ʤ ¸º
2005-05-09 2 2
2005-05-10 1 2
------------------------------------------
create table #tmp(rq varchar(10),shengfu nchar(1))
insert into #tmp values('2005-05-09','ʤ')
insert into #tmp values('2005-05-09','ʤ')
insert into #tmp values('2005-05-09','¸º')
insert into #tmp values('2005-05-09','¸º')
insert into #tmp values('2005-05-10','ʤ')
insert into #tmp values('2005-05-10','¸º')
insert into #tmp values('2005-05-10','¸º')
1)select rq, sum(case when shengfu='ʤ' then 1 else 0 end)'ʤ',sum(case when shengfu='¸º' then 1 else 0 end)'¸º' from #tmp group by rq
2) select N.rq,N.勝,M.負 from (
select rq,勝=count(*) from #tmp where shengfu='ʤ'group by rq)N inner join
(select rq,負=count(*) from #tmp where shengfu='¸º'group by rq)M on N.rq=M.rq
3)select a.col001,a.a1 ʤ,b.b1 ¸º from
(select col001,count(col001) a1 from temp1 where col002='ʤ' group by col001) a,
(select col001,count(col001) b1 from temp1 where col002='¸º' group by col001) b
where a.col001=b.col001
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select (case when a>b then a else b end ),
(case when b>c then b esle c end)
from table_name
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ÇëÈ¡³ötb_send±íÖÐÈÕÆÚ(SendTime×Ö¶Î)Ϊµ±ÌìµÄËùÓмǼ?(SendTime×Ö¶ÎΪdatetimeÐÍ£¬°üº¬ÈÕÆÚÓëʱ¼ä)
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select * from tb where datediff(dd,SendTime,getdate())=0
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