传智播客－Tree in SQL（译文）（3）
This has some predictable results that we can use for building queries. The root is always of the form (left = 1, right = 2 * (SELECT COUNT(*) from TreeTable)); leaf nodes always have (left + 1 = right); the BETWEEN predicate defines the subtrees; and so on. Here are some common queries that you can use to build others:
我们可以利用一些可预见的结果构建查询（表达式）。根部总是以这种形式构成（left = 1, right = 2 * (SELECT COUNT(*) from TreeTable)）；叶子节点则总是（left + 1 = right）；BETWEEN表达定义了子树；等等。这里有一些常用的查询，你可以用它们来组建更多其他（查询）：
1. Find an employee and all his/her supervisors, no matter how deep the tree.
查找一个雇员及他/她的所有上级，无论这颗树结构有多深。
SELECT P2.*
from Personnel AS P1, Personnel AS P2
WHERE P1.lft BETWEEN P2.lft AND P2.rgt
AND P1.emp = :myemployee;
2. Find the employee and all his/her subordinates. (This query has a nice symmetry with the first query.)
查找雇员及他/她所有下属。（这个查询与第一个查询形成良好的对称。）
SELECT P2.*
from Personnel AS P1, Personnel AS P2
WHERE P1.lft BETWEEN P2.lft AND P2.rgt
AND P2.emp = :myemployee;
3. Add a GROUP BY and aggregate functions to these basic queries and you have hierarchical reports. For example, the total salaries that each employee controls:
给这些基本查询添加GROUP BY（关键字）和总计函数这样你就有分级记录了。例如，每个雇员能支配的薪酬总数：
SELECT P2.emp, SUM(S1.salary)
from Personnel AS P1, Personnel AS P2,
Salaries AS S1
WHERE P1.lft BETWEEN P2.lft AND P2.rgt
AND P1.emp = S1.emp
GROUP BY P2.emp;
In the adjacency list method, this has to be done with a cursor.
在邻接列表模式里，必须依靠游标（cursor）才能这样做。
4. Find the level of each node, so you can print the tree as an indented listing.
查找每个节点的级别，这样你就能够以缩进列表形式打印这棵树了。
SELECT COUNT(P2.emp) AS indentation, P1.emp
from Personnel AS P1, Personnel AS P2
WHERE P1.lft BETWEEN P2.lft AND P2.rgt
GROUP BY P1.emp
ORDER BY P1.lft;
5. The nested set mod
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转载说明：给正在做系统和想做系统的人，SQL博大精深，你们会用到的。——mAysWINd
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Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
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Teacher(T#,Tname) 教师表
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group by linkname Having Count(*) > 1
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select max(id) as nid from tableName
group by linkname Having Count(id) > 1
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delete from table ......
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from RDB$RELATIONS
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SELECT RC.RDB$CONSTRAINT_NAME AS CONSTRAINT_NAME,
I.RDB$RELATION_NAME AS TABLE_NAME,
S.RDB$FIELD_NAME AS COLUMN_NAME
from RDB$RELATION_CONSTRAINTS ......
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select * from table1 where name=''zhangsan'' and tID > 10000
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