源贴：http://topic.csdn.net/u/20100417/19/ebdc216a-acc9-4e04-80f3-dbada0b4f3fe.html?74846
数据类型：
Code char(6)
CreateTime datetime
Price float
Status bit
数据如下：
Code CreateTime Price Status
031002 2008-10-17 15:00:15 3.58 1
031002 2008-10-17 15:00:16 5.53 1
031002 2008-10-17 15:00:17 4.54 1
031002 2008-10-17 15:00:18 4.44 1
031002 2008-10-17 15:00:19 4.34 1
031002 2008-10-17 15:00:20 4.24 1
031012 2008-10-17 15:00:15 3.58 0
031012 2008-10-17 15:00:16 5.53 0
031012 2008-10-17 15:00:17 4.54 0
031012 2008-10-17 15:00:18 4.44 0
031012 2008-10-17 15:00:19 4.34 1
031012 2008-10-17 15:00:20 4.24 1
031012 2008-10-17 15:00:18 3.51 0
031012 2008-10-17 15:00:19 3.52 0
031012 2008-10-17 15:00:20 2.50 0
031012 2008-10-17 15:00:21 3.51 0
031012 2008-10-17 15:00:22 3.52 0
031012 2008-10-17 15:00:23 2.50 0
031012 2008-10-17 15:00:24 3.51 0
031012 2008-10-17 15:00:25 3.52 0
031012 2008-10-17 15:00:26 2.50 0
031033 2008-10-17 15:00:21 4.53 0
031033 2008-10-17 15:00:22 3.55 0
031033 2008-10-17 15:00:23 3.55 0
031033 2008-10-17 15:00:24 5.57 0
031033 2008-10-17 15:00:25 5.57 1
031033 2008-10-17 15:00:26 5.57 1
031033 2008-10-17 15:00:27 5.57 1
031033 2008-10-17 15:00:28 5.57 1
我想要的结果是
031012 2008-10-17 15:00:19 4.34 1
031033 2008-10-17 15:00:25 5.57 1
得出这个结果的要求是: 按照Code分组，按照时间asc排序 Status
declare @XML XML
SET @XML='<root>
<OLDVALUE>
<H_Action id="1130">030</H_Action>
<D_Action>030</D_Action>
<OrderCompany>00220</OrderCompany>
<OrderNumber>10004035</OrderNumber> ......
