名次算法(sql server)(转自：爱新觉罗.毓华)
表jh03有下列数据：
name score
aa 99
bb 56
cc 56
dd 77
ee 78
ff 76
gg 78
ff 50
1. 名次生成方式1,Score重复时合并名次
SELECT * , Place=(SELECT COUNT(DISTINCT Score) from jh03 WHERE Score >= a.Score)
from jh03 a
ORDER BY Place
结果
Name Score Place
---------------- ----------------- -----------
aa 99.00 1
ee 78.00 2
gg 78.00 2
dd 77.00 3
ff 76.00 4
bb 56.00 5
cc 56.00 5
ff 50.00 6
2. 名次生成方式2 , Score重复时保留名次空缺
SELECT * , Place=(SELECT COUNT(Score) from jh03 WHERE Score > a.Score) + 1
from jh03 a
ORDER BY Place
结果
Name Score Place
--------------- ----------------- -----------
aa 99.00 1
ee 78.00 2
gg 78.00 2
dd 77.00 4
ff 76.00 5
bb 56.00 6
cc 56.00 6
ff 50.00 8
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