名次算法(sql server)(转自：爱新觉罗.毓华)

表jh03有下列数据：
name　score
aa　　99
bb　　56
cc　　56
dd　　77
ee　　78
ff　　76
gg　　78
ff　　50
1. 名次生成方式1,Score重复时合并名次
SELECT *　,　Place=(SELECT COUNT(DISTINCT Score) from jh03 WHERE Score >= a.Score)
from jh03 a
ORDER BY Place
结果
Name Score Place
---------------- ----------------- -----------
aa 99.00 1
ee 78.00 2
gg 78.00 2
dd 77.00 3
ff 76.00 4
bb 56.00 5
cc 56.00 5
ff 50.00 6
2. 名次生成方式2 , Score重复时保留名次空缺
SELECT * , Place=(SELECT COUNT(Score) from jh03 WHERE Score > a.Score) + 1
from jh03 a
ORDER BY Place
结果
Name Score Place
--------------- ----------------- -----------
aa 99.00 1
ee 78.00 2
gg 78.00 2
dd 77.00 4
ff 76.00 5
bb 56.00 6
cc 56.00 6
ff 50.00 8