vb用api调用对话框
建一个模块
Public Declare Function GetOpenFileName Lib "comdlg32.dll" Alias "GetOpenFileNameA" (pOpenfilename As OPENFILENAME) As Long
Public Type OPENFILENAME
lStructSize As Long
hwndOwner As Long
hInstance As Long
lpstrFilter As String
lpstrCustomFilter As String
nMaxCustFilter As Long
nFilterIndex As Long
lpstrFile As String
nMaxFile As Long
lpstrFileTitle As String
nMaxFileTitle As Long
lpstrInitialDir As String
lpstrTitle As String
flags As Long
nFileOffset As Integer
nFileExtension As Integer
lpstrDefExt As String
lCustData As Long
lpfnHook As Long
lpTemplateName As String
End Type
窗体上放一个编辑框和按钮
Private Sub Command1_Click()
Dim ofn As OPENFILENAME
Dim strRtn As String
ofn.lStructSize = Len(ofn)
ofn.hwndOwner = Me.hwnd
ofn.hInstance = App.hInstance
ofn.lpstrFilter = "所有文件"
ofn.lpstrFile = Space(254)
ofn.nMaxFile = 255
ofn.lpstrFileTitle = Space(254)
ofn.nMaxFileTitle = 255
ofn.lpstrInitialDir = App.Path
ofn.lpstrTitle = "打开文件"
ofn.flags = 6148
rtn = GetOpenFileName(ofn)
If rtn >= 1 Then
Text1.Text = ofn.lpstrFile
Else
Text1.Text = "Cancel Was Pressed"
End If
End Sub
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Option Explicit
Private Const INTERNET_OPEN_TYPE_DIRECT = 1
Private Const scuseragent = "vb wininet"
Private Const INTERNET_FLAG_PASSIVE = &H8000000
'调用设置环境
Private Declare Function InternetOpen Lib "wininet.dll" Alias "InternetOpenA" (ByVal sAgent As String, ByVal lAccessType As Long ......
VERSION 5.00
Begin VB.Form Form2
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VB6
在程序运行时用如下语句:
if app.PrevInstance=true then
end
end if
VB 2005:
1. 在VB2005中,打开"属性"页,启用"应用程序“框架, 选中"
单实例应用程序"前面复选框,就行了。
......
Option Explicit
Private Const NCBASTAT = &H33
Private Const NCBNAMSZ = 16
Private Const HEAP_ZERO_MEMORY = &H8
Private Const HEAP_GENERATE_EXCEPTIONS = &H4
Private Const NCBRESET = &H32
Private Type NCB
ncb_command As Byte
ncb_retcode As Byte
ncb_lsn As Byte
ncb_num As Byte ......