用XmlReader 取xml文件节点的值

在项目中，同一个配置在不同的目录下要有不同的值，而目录又是不确定的，这时就需要将配置信息存放在相应的目录中，在运行时根据路径去取
方法：用xml文件存储，放在使用目录下，用下面方法获取配置信息
public class yzzConfig
{
/// <summary>
/// 获取Xml文件配置信息
/// </summary>
/// <param name="node">节点名</param>
/// <param name="path">文件路径</param>
/// <returns></returns>
public static string AppSettings(string node, string path)
{
string result = string.Empty;
try
{
//XmlReaderSettings settings = new XmlReaderSettings();
//settings.IgnoreComments = true;
//settings.IgnoreProcessingInstructions = true;
//settings.IgnoreWhitespace = true;

using (XmlReader reader = XmlReader.Create(path))//, settings))
{
reader.MoveToContent();
while (reader.Read())
{
if (reader.NodeType == XmlNodeType.Element && reader.Name == node)
{
result = reader.ReadInnerXml();
break;
}
}
reader.Close();
}
}
catch (Exception ex)
{
throw ex;
}
return result;
}
}
XML文件示例
<?xml version="1.0" encoding="utf-8" ?>
<configuration>
<yzzSettings>
<xmlxslt>test</xmlxslt>
</yzzSettings>
<configSections>

调用示例
protected void Button1_Click(object sender, EventArgs e)
{
Response.Write(yzzConfig.AppSettings("xmlxslt", string.Format("{0}\\yzzconfig.xml",
Request.Ph