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id hit times
1 1 2008Äê2ÔÂ19ÈÕ
2 26 2008Äê2ÔÂ27ÈÕ
3 32 2008Äê2ÔÂ27ÈÕ
select sum(hit)as wk,times from hit where id=1005 group by times
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1 2009Äê12ÔÂ10ÈÕ
2 2009Äê12ÔÂ16ÈÕ
1 2009Äê12ÔÂ17ÈÕ
1 2009Äê12ÔÂ19ÈÕ
983 2009Äê12ÔÂ1ÈÕ
1262 2009Äê12ÔÂ2ÈÕ
1201 2009Äê12ÔÂ3ÈÕ
857 2009Äê12ÔÂ4ÈÕ
951 2009Äê12ÔÂ5ÈÕ
924 2009Äê12ÔÂ6ÈÕ
312 2009Äê12ÔÂ7ÈÕ
4 2009Äê12ÔÂ8ÈÕ
2 2009Äê12ÔÂ9ÈÕ
select sum(hit)as wk,times from hit where id=1005 and replace(replace(replace(times,'Äê','-'),'ÔÂ','-'),'ÈÕ','')>=replace(replace(replace('2009Äê12ÔÂ20ÈÕ','Äê','-'),'ÔÂ','-'),'ÈÕ','') group by times
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1201 2009Äê12ÔÂ3ÈÕ
857 2009Äê12ÔÂ4ÈÕ
951 2009Äê12ÔÂ5ÈÕ
924 2009Äê12ÔÂ6ÈÕ
312 2009Äê12ÔÂ7ÈÕ
4 2009Äê12ÔÂ8ÈÕ
2 2009Äê12ÔÂ9ÈÕ
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SQL code:
select sum(hit)as wk,times from hit where id=1005 and CONVERT(DATETIME,replace(replace(replace(ti
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Microsoft SQL Administrator
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A detail oriented Microsoft SQL Administratorwith excellent problem solving, analyti ......
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